java - List names and number of occurrences -


so task read file following names:

alice bob  james   richard   bob   alice   alice   alice   james   richard   bob  richard   bob   stephan   michael   henry

and print out each name value of occurrence e.g "alice - <4>".
got working, basically. problem have last name (stephan - <1>) missing in output , can't work properly.. it's because used [i-1] said, i'm not getting right solution here.
well, here's code..

package assignment4;  import java.io.filenotfoundexception; import java.io.filereader; import java.io.ioexception; import java.io.inputstreamreader; import java.io.bufferedreader; import java.util.arrays;  public class reportuniquenames {      public static void main(string[] args) {         // todo auto-generated method stub          system.out.println ("       programm counts words, characters , lines!\n");         system.out.println ("please enter name of .txt file:");          bufferedreader input = new bufferedreader(new inputstreamreader (system.in));          bufferedreader read = null;         string file = "";         string text = "";         string line = "";         boolean unique = true;         int namecounter = 1;                  try {              file = input.readline();             read = new bufferedreader (new filereader(file));             while ((line = read.readline()) != null) {                 text += line.trim() + " ";                               }          } catch (filenotfoundexception e) {             system.out.println("file not found.");                   } catch (ioexception e) {             system.out.println("an error has occured.");                     }          string textarray[] = text.split(" ");         arrays.sort(textarray);          (int i=0; < textarray.length; i++) {              if (i > 0 && textarray[i].equals(textarray[i-1])) {                 namecounter++;                 unique = false;             }              if (i > 0 && !textarray[i].equals(textarray[i-1]) && !unique) {                     system.out.println("<"+textarray[i-1]+"> - <"+namecounter+">");                     namecounter = 1;                     unique = true;             } else if (i > 0 && !textarray[i].equals(textarray[i-1]) && unique) {                 //namecounter = 1;                 system.out.println("<"+textarray[i-1]+"> - <"+namecounter+">");             }                     }      }  }

so that's it.. 1 of me out.

edit:
wow, many different approaches.
first of of help.
i'll through suggested solutions , maybe restart bottom ;).
give heads when i'm done.

you use map (that emulates "multiset") purpose of counting words:

string textarray[] = text.split(" ");  // treemap gives sorting alphabetical order "for free" map<string, integer> wordcounts = new treemap<>();  (int = 0; < textarray.length; i++) {     integer count = wordcounts.get(textarray[i]);     wordcounts.put(textarray[i], count != null ? count + 1 : 1); }  (map.entry<string, integer> e : wordcounts.entryset()) {     system.out.println("<" + e.getkey() + "> - <" + e.getvalue() + ">"); }

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