bash - using sed to cut a part of file -


cat /opt/inventory.txt

################################################################################### begin_detail_of 5678 request_no of activity 5678 testproject requester of project xyz xyz@test.com end_of 5678 #################################################################################### ################################################################################### begin_detail_of 1234 request_no of activity 1234 testproject requester of project xyz xyz@test.com end_of 1234 ####################################################################################

when use number 1234 below expected output below

cat /opt/inventory.txt | sed -n -e '/begin_detail_of\ 5678/,$p' | sed -e '/end_of\ 5678/,$d' begin_detail_of 5678 request_no of activity 5678 testproject requester of project xyz xyz@test.com have new mail in /var/spool/mail/root

but when substitute number variable output not expected below

[root@centoo script]# export num=5678 [root@centoo script]# echo $num 5678 [root@centoo script]# cat /opt/inventory.txt | sed -n -e '/begin_detail_of\ $num/,$p' | sed -e '/end_of\ $num/,$d' [root@centoo script]#

please solve issue.

you don't need 2 sed commands , make sure use double quotes while using shell variable in expression. can in same sed this:

num=5678 sed -n "/begin_detail_of $num/,/end_of $num/{/end_of $num/d;p;}" file begin_detail_of 5678 request_no of activity 5678 testproject requester of project xyz xyz@test.com

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