c - Using sizeof with char *array[] -

i new programming. learning c , java.

i have array -

char *array = {"zero", "one", "two", "three"};

from link can print array content -

printf("%s %s", array[0], array[1]); //zero 1

but question how can print length of referenced array[0], array[1] , on. know can thing -

printf("%d\n", sizeof("zero");

but can print size using array variable itself.

i have tried different ways -

printf("%d\n", sizeof(array[0]);  //4 printf("%d\n", sizeof(*array[0]);  //1

but each time wrong answer.

thanks

you need strlen.

printf("%d\n", (int) strlen(array[0]));

Call