How to get a MySQL field's content with PHP? -


i've been working on website's database , had problem recently: want user read field of row, when field of same row submitted. i.e:

user_id=1 user_name=fran user_pass=potato referedby_id=0 referedby_name=empty

when going inside www.website.com/form.php?referedby_id=1

i want user see "so, fran refered you?"

i've been learning php , decided try this:

$referedbyid = mysqli_real_escape_string($con,$_post["referedby_id"]); //in case it's 1 because of url  $sel_referedbyname = "select user_name users user_id='$referedbyid'"; //then should select of user_name "fran"  $run_referedbyname = mysqli_query($con, $sel_referedbyname); //then query select  $check_referedbyname = mysqli_fetch_field($run_referedbyname); //and 1 content of query's result  $refername = $check_refername->user_name; //as query result object want convert text  if(isset($_post["register"]) && $check_user == 0 && $check_email == 0 && $pass == $pass2){ //if right , user/email not exist  mysqli_query($con,"insert users (user_name, user_email, user_pass, refer_id, refer_name) values ('$user', '$email', '$pass', '$referid', '$refername')"); //it's submitted database other values.  mysqli_close($con); //and finish connection db.

the problem when try , check database, referedby_name field empty. syntax error? or because didn't convert text properly?

in case $referedbyname not text, how can convert properly? because i'm using fetch_field function wrong?

additional info: $referedbyid being called (i think) in post form html

<form action="register.php" method="post" onsubmit="validate();">  <table width="500" align="center" bgcolor="skyblue">  <tr align="center">  <td colspan="3"><h2>registrarse</h2></td>  </tr>  <tr>  <td align="right"><b>nombre de usuario:</b></td>  <td><input type="text" name="user" required="required"/></td>  </tr>  <tr>  <td align="right"><b>email:</b></td>  <td><input type="email" name="email" required="required"/></td>  </tr>  <tr>  <tr>  <td align="right"><b>contraseña:</b></td>  <td><input type="password" id="pass" name="pass" required="required"/></td>  </tr>  <tr>  <td align="right"><b>verificar contraseña:</b></td>  <td><input type="password" id="pass2" name="pass2" required="required"/></td>  </tr>  <tr align="center"> <td colspan="3"> <input type="hidden" name="referedby_id" value="<?php echo $_get["referedby_id"]; ?>"/> <input type="submit" name="register" value="registrarse"/></td> </tr>  </table>  </form>

i don't know why downvotes, tried clear , specific could... anyways, if else has trouble finding the value of specific field use mysqli_fetch_assoc(mysqli_query($conect, $select))['name of sql field']

mysqli_fetch_field($result) show information field, type of input, name of table, name of column, etc.

hope that's useful same issue. bye.


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