sql - Where clause with multiple values -


i new sql , using ms sql server management studio 2014. have 3 tables called pizza, pizza_topping , topping. want list pizzas have topping1 , topping2 toppings. have came with,

select  pizza.pizzaid, pizza.pizzaname, topping.toppingname  pizza left join pizza_topping on pizza.pizzaid = pizza_topping.pizzaid  left join topping on topping.toppingid = pizza_topping.toppingid  topping.toppingname in ('topping1', 'topping2')

and gives me

pizzaid    pizzaname        toppingname -------- ---------------- -------------- pz002   |   pizza1       |    topping1 pz002   |   pizza1       |    topping2 pz010   |   pizza5       |    topping1 pz010   |   pizza5       |    topping2 pz011   |   pizza6       |    topping1 pz012   |   pizza7       |    topping2

i need first 4 rows because last 2 pizzas have 1 of toppings not both. have tried well,

group pizza.pizzaid,pizza.pizzaname, topping.toppingname having count(toppingname) >= 2

but didn't give expected result. line can used if going display pizzaid , pizzaname want display toppingname well.

to more clear, expecting

pizzaid    pizzaname        toppingname -------- ---------------- -------------- pz002   |   pizza1       |    topping1 pz002   |   pizza1       |    topping2 pz010   |   pizza5       |    topping1 pz010   |   pizza5       |    topping2

please tell me how achieve result. thanks

i think done more if can count() in subquery , join pizzaid's have count greater 1 this:

select q1.pizzaid     ,q1.pizzaname     ,t.toppingname (     select pizza.pizzaid         ,pizza.pizzaname         ,count(topping.toppingname) total_count     pizza     inner join pizza_topping on pizza.pizzaid = pizza_topping.pizzaid     inner join topping on topping.toppingid = pizza_topping.toppingid     group pizza.pizzaid         ,pizza.pizzaname     having count(topping.toppingname) > 1     ) q1 inner join pizza_topping pt on q1.pizzaid = pt.pizzaid inner join topping t on t.toppingid = pt.toppingid t.toppingname in ('topping1', 'topping2')

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