arrays - Deleting dynamic char** in C++ -

disclosure: i'm trying solve challenge strict time , memory limits. use vectors , strings, here need fastest , smallest solution (with vectors ran above time limit), turned dynamic arrays of char*. relevant parts of code:

char** substrings(string s, int* n){     *n = 0;     ...     ////////////////////////////////     char** strings = new char*[*n];     ////////////////////////////////     (int = 0; < s.length(); i++){         (int j = 1; j < s.length() - + 1; j++){             ...             strings[si] = tmp;             ...         }     }     return strings; }  int main(){     ...     (int ti = 0; ti < t; ti++){         cin >> s;         char** substr = substrings(s, &n);         ...          (int = 0; < n; i++){             delete substr[i];         }     }     return 0; } 

everything runs fine without deleting array (of arrays), unacceptable, how go this? i've tried lot of variations seemed logical runtime errors.

it similar allocating, in reverse order, , using delete[] instead of new[]:

for(int = 0; <  length; i++)      delete[] strings[i]; // delete each pointer in char** strings delete[] strings; // delete array of pointers 

i assumed here length length of array of pointers char*. looks perform first round of de-allocation

for (int = 0; < n; i++){         delete substr[i]; // need delete[] substr[i] here 

but delete instead of delete[], need delete[] substr[i] instead, guess substr[i] char* pointer pointing first element of array of chars allocated new[]. need additional

delete[] substr;