android - How to check if two rectangles are "on" each other -


i want check if enemy_green_light (enemy_green_light_xenemy_green_light_y) , player (x, y) touched each other. however, code doesn't want, , can met though didn't. (x, y) left corner coordinates. thanks!

boolean before_x=(x<enemy_green_light_x)&&(x+player.getwidth()>enemy_green_light_x);     boolean after_x=(x>enemy_green_light_x)&&(enemy_green_light_x+enemy_green_light.getwidth()>x);     boolean before_y=(y<enemy_green_light_y)&&(y+player.getheight()>enemy_green_light_y);     boolean after_y=(y>enemy_green_light_y)&&(enemy_green_light_y+enemy_green_light.getheight()>y);     if(before_x||after_x)         if(before_y||after_y)         {             pressed=true;         }

edit: tried code too, , didn't work.

float p_y_1,p_y_2,p_x_1,p_x_2,e_y_1,e_y_2,e_x_1,e_x_2;     p_y_1=y;     p_y_2=y+player.getheight();     p_x_1=x;     p_x_2=x+player.getwidth();     e_y_1=enemy_green_light_y;     e_y_2=enemy_green_light_y+enemy_green_light.getheight();     e_x_1=enemy_green_light_x;     e_x_2=enemy_green_light_x+enemy_green_light.getwidth();     if(!(p_y_2<e_y_1||p_y_1>e_y_2||p_x_2<e_x_1||p_x_1>e_x_2))         pressed=true;

here have explanation how determine if 2 rectangles overlap

enter image description here

the solution expression

! ( p2.y < p3.y || p1.y > p4.y || p2.x < p3.x || p1.x > p4.x )

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