php - include files by ID on same page -

is there way this?

including file:

<?php $_get["id"]; case "fruits": include 'fruits.php'; ?> 

fruits.php:

<?php $id = 'fruits'; echo 'hello fruits'; ?> 

i want include files id specified in included file. help.

your code incomplete, here's attempt @ solution problem.

<?php // id parameter , change standard form // (standard form lower case no leading or trailing spaces) $fileid = strtolower(trim($_get['id']));  // check file id , load relevant file switch( $fileid ){     case 'fruits':         require('fruits.php');         break;     case 'something_else':         require('something_else.php');         break;     /* ... other test cases... */     default:         // unknown file requested         echo 'an error has occurred. unknown file requested.'; } ?> 

alternatively, if have long list of possible files, recommend following:

<?php // id parameter , change standard form // (standard form lower case no leading or trailing spaces) $fileid = strtolower(trim($_get['id']));  // array of possible options: $fileoptions = array('fruits', 'something_else', 'file1', 'file2' /* ... etc... */);  // check if fileid valid if(in_array($fileid, $fileoptions, true)){     // fileid valid option     $fullfilename = $fileid . '.php';     require($fullfilename); }else{     // invalid file option     echo 'an error has occurred. unknown file requested.'; } ?> 

switch statements lot of cases can long , can reduce readability. hence, second solution uses array , in_array function reduce code length. allows see/manage files permitted.