c++ - What is the difference between (void*) and (void(*)(argument type)) cast? -

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• why function pointers , data pointers incompatible in c/c++? 14 answers

void funcptr(int a);  int main(){    int k=1;    void (*funcptr2)(int);     funcptr2 = (void*)(funcptr);    // funcptr2 = (void(*)(int))(funcptr);     (*funcptr2)(k);    return 0; }  void funcptr(int a){    printf("%d", a); } 

what difference between (void*) , (void(*)(argument type) in function pointer type casting?

as result, not occur warning.

is wrong? (void*) type casting

is wrong? (void*) type casting

yes, is.

c standard doesn't allow conversion of function pointer object pointer or assignment between them. if compiler warning level, may warnings/errors such compiling with:

gcc -wall -wextra -pedantic-errors -std=c11 file.c 

i not sure why thought casting function pointer. provided function pointer type matches function, assign it:

 funcptr2 = funcptr; 

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aside:

you can use function pointer function:

 funcptr2(k); 

and use standard prototype main such as:

int main(void)