android - Optimize way to use ViewPager? -

i'm writing application need show 100 page in viewpager. there facility jump 1 index direct random index page. here every page self contain list of item.

now if user viewpager.current(index) jump 1 random index page..then ui stuck moment , display.

so avoid thought implement 7 adapter page view..where these 100(getcount()) page reuses these 7 page.

but im'm getting

e/androidruntime(25961): java.lang.illegalstateexception: fragment added: arraylistfragment{24dad9b6 #0 id=0x7f060009} e/androidruntime(25961):    @ android.support.v4.app.fragmentmanagerimpl.addfragment(fragmentmanager.java:1192) e/androidruntime(25961):    @ android.support.v4.app.backstackrecord.run(backstackrecord.java:616) e/androidruntime(25961):    @ android.support.v4.app.fragmentmanagerimpl.execpendingactions(fragmentmanager.java:1484) e/androidruntime(25961):    @ android.support.v4.app.fragmentmanagerimpl.executependingtransactions(fragmentmanager.java.  

i'm using fragmentstatepageradapter adapter implementation.

following snap of code i'm using

static final int num_items = 100;     private int max_available_count = 7;     private arraylist<arraylistfragment> listfragment = new arraylist();      public class myadapter extends fragmentstatepageradapter {          public myadapter(fragmentmanager fragmentmanager) {             super(fragmentmanager);              (int = 0; < max_available_count; i++) {                 listfragment.add(arraylistfragment.newinstance(i));             }         }          @override         public int getcount() {             return num_items;         }          @override         public fragment getitem(int position) {              original = position;              if (position >= max_available_count - 1) {                 int newposition = position % max_available_count;                  position = newposition;             }              fragment fragment = listfragment.get(position);              return fragment;         }     } 

any suggestion i'm doing wrong here. or other suggestion achieve it!!

your error because manipulating position in getitem() method. can't because @ point return fragment tied other page , exception above. , storing references fragments bad practice, return new instance of fragment object.