c++ - How parse datetime format from datebase? -


the database (sqlite) has field of type real values of form (42153.659595). how translate value in form "dd.mm.yy hh:mm:ss" if 42153.659595 = 29.05.2015 15:49:49 ?

you can explicit calendar system require: http://www.sqlite.org/lang_datefunc.html

select julianday('now') - julianday('1776-07-04');

in principle don't "parse" (you mean: interpret raw representation). use sqlite api/builtin sql functions you

in interest of information:

  • the date , time functions use a subset of is0-8601 date , time formats.
  • the datetime() function returns "yyyy-mm-dd hh:mm:ss". julianday() function returns julian day - number of days since noon in greenwich on november 24, 4714 b.c. (proleptic gregorian calendar)
  • the date() function returns date in format: yyyy-mm-dd. time() function returns time hh:mm:ss.

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