bash - Passing multiple parameters to shell script and parsing them -

i trying run following program, need pass multiple options command executed. here example: giving inputs

/test.sh -s -n 

script test.sh:

#! /bin/bash #set -x while [ $# -gt 0 ]      case $1 in     -s) service=$2     shift     ;;     -n) node=$3      command     break      ;;    *) echo "invalid argument"     break     ;;  esac  done 

using getopts built-in command in bash:

#!/bin/bash  service="default" node="default"  while getopts 's:n:' opt;     case $opt in         s)  service="$optarg" ;;         n)  node="$optarg"    ;;         *)  exit 1            ;;     esac done  echo "service = '${service}'" echo "node    = '${node}'" 

testing it:

$ ./test.sh service = 'default' node    = 'default'  $ ./test.sh -s hello -n world service = 'hello' node    = 'world'  $ ./test.sh -n world -s hello service = 'hello' node    = 'world'  $ ./test.sh -e eh ./test.sh: illegal option -- e