python - How to get numpy array from multiple lists of same length and sort along an axis? -


i have simple question ,how numpy array multiple lists of same length , sort along axis ?

i'm looking like: 

a = [1,1,2,3,4,5,6] b = [10,10,11,09,22,20,20] c = [100,100,111,090,220,200,200] d = np.asarray(a,b,c) print d >>>[[1,10,100],[1,10,100],[2,11,111].........[6,20,200]]

2nd question : , if achieved can sort along axis (for eg. on values of list b)?

3rd question : can sorting done on range ? eg. values between b+10 , b-10 while looking @ list c further sorting. like

[[1,11,111][1,10,122][1,09,126][1,11,154][1,11,191]  [1,20,110][1,25,122][1,21,154][1,21,155][1,21,184]]

you can zip array:

a = [1, 1, 2, 3, 4, 5, 6] b = [10, 10, 11, 9, 22, 20, 20] c = [100, 100, 111, 90, 220, 200, 200] d = np.asarray(zip(a,b,c)) print(d) [[  1  10 100]  [  1  10 100]  [  2  11 111]  [  3   9  90]  [  4  22 220]  [  5  20 200]  [  6  20 200]]  print(d[np.argsort(d[:, 1])]) # sorted copy [[  3   9  90] [  1  10 100] [  1  10 100] [  2  11 111] [  5  20 200] [  6  20 200] [  4  22 220]]

i don't know how inplace sort without doing like:

d = np.asarray(zip(a,b,c))  d.dtype = [("0", int), ("1", int), ("2", int)] d.shape = d.size d.sort(order="1")

the leading 0 make 090 octal in python2 or invalid syntax in python3 removed it.

you can sort zipped elements before pass the:

from operator import itemgetter zipped = sorted(zip(a,b,c),key=itemgetter(1))   d = np.asarray(zipped) print(d) [[  3   9  90]  [  1  10 100]  [  1  10 100]  [  2  11 111]  [  5  20 200]  [  6  20 200]  [  4  22 220]]

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