objective c - How to find the number of gaps between words in an NSString? -


given nsstring containing sentence determine number of gaps between words.

i use [[thestring componentsseparatedbystring:@" "].

but work if each gap single space character, there multiple.

you can use nsregularexpression, like:

nsstring *test = @"the quick        brown fox  jumped on    lazy dog"; nsregularexpression *regex = [nsregularexpression regularexpressionwithpattern:@"\\s+" options:0 error:null]; nsuinteger num = [regex numberofmatchesinstring:test options:0 range:nsmakerange(0, test.length)]; nslog(@"num: %lu", num);

the regular expression "\s+" matches 1 or more whitespace characters (it's written here "\" because need literal backslash in nsstring). numberofmatchesinstring:options:range: counts each run of 1 or more whitespace characters match, want.


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