matlab - Using a clear portion of the picture to recreate a PSF -


i'm trying unblur blurred segments of following picture.

enter image description here

the original psf not given, proceeded analyse blurred part , see whether there word make out. found out make out "of" in blurred section. cropped out both the blurred "of" , counterpart in clear section -> seen below.

enter image description here

i thought through lectures in fft divide blurred(frequency domain) particular blurring function(frequency domain) recreate original image.

i thought if unblurred(frequency domain)\blurred(frequency domain), original psf retrieved. please advise on how this.

this code.

img = im2double(imread('c:\users\adhil\desktop\matlab pics\image1.jpg'));  blurred = imcrop(img,[205 541 13 12]);  unblurred = imcrop(img,[39 140 13 12]);    ub = fftshift(unblurred);  ub = fft2(ub);   ub = ifftshift(ub);     f_1a = zeros(size(b));  idx = 1 : size(blurred, 3)      b = fftshift(blurred(:,:,idx));      b = fft2(b);       b = ifftshift(b);        uba = ub(:,:,idx);      tmp = uba ./ b;       tmp = ifftshift(tmp);       tmp = ifft2(tmp);       tmp = fftshift(tmp);       [j, p] = deconvblind(blurred,tmp);        end          subplot(1,3,1);imshow(blurred);title('blurred');  subplot(1,3,2);imshow(unblurred);title('original unblurred');  subplot(1,3,3);imshow(j);title('attempt @ unblurring');

this code, however, not work, , i'm getting following error.

error using deconvblind  expected input number 2, initpsf, real.    error in deconvblind>parse_inputs (line 258)  validateattributes(p{1},{'uint8' 'uint16' 'double' 'int16' 'single'},...    error in deconvblind (line 122)  [j,p,numit,dampar,readout,weight,sizei,classi,sizepsf,funfcn,funarg] = ...    error in test2 (line 20)      [j, p] = deconvblind(blurred,tmp);

is way recreate original psf?


Comments

Post a Comment

Popular posts from this blog

angularjs - ADAL JS Angular- WebAPI add a new role claim to the token -

i have created angular spa webapi backend using adal js authentication.as there no roles in ad, need manually add role claims in order give users access different api controllers. the roles stored in database. expecting inject claim through call webapi after authentication ad. webapi code might this. identity.addclaim(new claim("role", "user")); var ticket = new authenticationticket(identity, props); var accesstoken = startup.oauthbeareroptions.accesstokenformat.protect(ticket); is possible replace adal idtoken new token? is viable solution or there other better way handle this? as initial token generated azuread, possible edit token add new claim? appreciated. graph api supporting group claims. see here: http://justazure.com/azure-active-directory-part-4-group-claims/ if @ examples on page, users assigned groups , app can check group in claims. in current version of portal, need app manifest , modify it.
Read more

php - CakePHP HttpSockets send array of paramms -

i problem when make request (i can request). $link = 'http://uri/path/?param1=1&sid=2&sid=3&sid=4' $http = $httpsocket = new httpsocket(); $res = $httpsocket->get($link); if check request pr($http); i see : [line] => /url/path/?param1=1&sid%5b0%5d=2&sid%5b1%5d=3&sid%5b2%5d=4 http/1.1 and i'm getting empty response because server doesn't know parameters sid%5b0%5d=2 when try send parameters array : $data = array('param1' => '1', 'sid' => array('2','3', '4')); i see same changes %5b0%5d - additional indexes. how fix it? unfortunately , can not change server side, if send request in browser, i'll normal response in json format. when make request, can parameters this: $param1 = $_get['param1']; $sid= $_get['sid']; tip: use diferente names parameters. have multiples sid. use sid1, sid2, sid3... update: can parameters this:
Read more

node.js - Using Node without global install -

i'm working on few node & electron (atom shell) projects , i'm curious how them work without user having install node globally. i've seen few applications including node directory in project contains node.exe binary. how go setting node project use binary? edit: thought should add, i've searched everywhere answer this, unrelated results.
Read more