sql server 2008 - SQL group by on one column with other columns selected -


i have function returns results below, how can remove duplicate rows? group how build function? , use inner joins on 'h' fields.

select         action.holiday_id,          action.id,         --h.holiday_name,          --h.date_start,         --h.date_end,         (select count(distinct action.holiday_id) action) 'count'  action   --inner join holiday_ref h on action.holiday_id=h.holiday_id action.delete_date null --group action.holiday_id   holiday_id id count 31         5  3 31         6  3 31         8  3 332        7  1

so like:

31  3  332 1

this should work.

with cte ( select holiday_id,         id,         holiday_name,         date_start,         date_end,         row_number() on (partition holiday_id order holiday_id) [index] action ) select holiday_id, id, holiday_name, date_start, date_end,        (select count(*) action          holiday_id = cte.holiday_id , delete_date null) [count] cte [index] = 1

edit: checks delete_date well

http://sqlfiddle.com/#!6/6d8ad/2


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