ios - contractDictionary.Type does not have a member named aDictionary -


the following code produces error

contractdictionary.type not have member named adictionary

but don't understand why or how fix it.

import foundation  class contactdictionary {  var adictionary:[contact] = [contact]() var bdictionary:[contact] = [contact]() var cdictionary:[contact] = [contact]() var ddictionary:[contact] = [contact]() var edictionary:[contact] = [contact]() var fdictionary:[contact] = [contact]() var gdictionary:[contact] = [contact]() var hdictionary:[contact] = [contact]() var idictionary:[contact] = [contact]() var jdictionary:[contact] = [contact]() var kdictionary:[contact] = [contact]() var ldictionary:[contact] = [contact]() var mdictionary:[contact] = [contact]() var ndictionary:[contact] = [contact]() var odictionary:[contact] = [contact]() var pdictionary:[contact] = [contact]() var qdictionary:[contact] = [contact]() var rdictionary:[contact] = [contact]() var sdictionary:[contact] = [contact]() var tdictionary:[contact] = [contact]() var udictionary:[contact] = [contact]() var vdictionary:[contact] = [contact]() var wdictionary:[contact] = [contact]() var xdictionary:[contact] = [contact]() var ydictionary:[contact] = [contact]() var zdictionary:[contact] = [contact]() var numdictionary:[contact] = [contact]()   var contactdictionary:(string, [contact]) = ["a": adictionary, "b": bdictionary, "c": cdictionary, "d": ddictionary, "e": edictionary, "f": fdictionary, "g": gdictionary, "h": hdictionary, "i": idictionary, "j": jdictionary, "k": kdictionary, "l": ldictionary, "m": mdictionary, "n": ndictionary, "o": odictionary, "p": pdictionary, "q": qdictionary, "r": rdictionary, "s": sdictionary, "t": tdictionary, "u": udictionary, "v": vdictionary, "w": wdictionary, "x": xdictionary, "y": ydictionary, "z": zdictionary, "#": numdictionary] }

do need declare variables elsewhere or in different way?


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