templates - Django regroup using group -

so have this

| element | brand | 1 b 2 c 2 d 1

how do group them brands doesnt repeat, mean dont want show brands twice, want render each brand once. note : brand foreign key

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class productos(models.model):     modelo = models.charfield(max_length=50)     tipo = models.foreignkey("tiposopciones", null=true, blank=true, related_name='productos_tipo')     marca = models.manytomanyfield(marcasopciones, related_name='productos_marca') 

i want show marca field once, not repeat it. tried it's repeating it:

                {% sth in productos.all %}                 {% ifequal articulo.tipos|slugify sth.tipo|slugify %}                 <li>                     <a href="#">                             {% sthelse in sth.marca.all %}                                  {{ sthelse }}                              {% endfor %}                     </a>                 </li>                 {% endifequal %}             {% endfor %} 

so how should group ?

looking @ code think want show marcas related articulo via product.type. scenario think don't need make grouping, can find marcas interested in. here mean:

#in view #add .distinct() if duplicates marcas = marcasopciones.object.filter(productos_marca__tipo=articulo.tipos)   #in template {% sthelse in marcas %}     <li><a href="#">{{ sthelse }}</a></li> {% endfor %} 

there 1 possible drawback approach - not using |slugify tag create match. possible solution create slug fields both models.

however, if approach doesn't suit you. advice move matching logic in view , again send needed marcas in template.

#in view django.template.defaultfilters import slugify  marcas = [] sth in productos.all():     if slugify(articulo.tipos) == slugify(sth.tipo):         sthelse in sth.marca.all():             if sthelse not in marcas:                 marcas.append(sthelse)                 #if need product match marca                 #you can add here                 #sthelse.product = sth