select - MySQL summing verses and n biggest results -


i've table looking more or less that:

**day**   | **mileage** ---------------- 1     | 13  2     | 2  3     | 25  4     | 15  5     | 20  6     | 8  7     | 17  8     | 12  9     | 16  10    | 5

how write sql query:

  1. returning total mileage firts nth day without using php? example, day 1:13, day 2: 15, day 3: 40.
  2. how 5 biggest mileages without using limit?

for sum up:

select mday, (select sum(miles) mm s s.mday <= mm.mday)  tot_miles mm;

for 5 biggest mileage per day

select mday, miles mm order miles desc limit 5

change column names , table name match yours.

since added "no use of limit", odd, can try this:

set @r =0; select * ( select *, @r :=@r+1 r mm order miles desc) e r<=5

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