python - printing a dictionary with specific format -

i done project , want print results. have dictionary this: {('a',): 4, ('b',): 5, ('c', 'd'): 3, ('e', 'f'): 4, ('g', 'h'): 3, ('i',): 3}

the key in pair key-value 1 element , in others 2 or three. , want print in format, elements 1 key in 1 line, elements 2 keys in new line etc...

(elem,) (elem1, elem2, ..., elem_n) 

i tried this:

itemdct //my dict result = [itemdct] csv_writer = csv.writer(sys.stdout, delimiter=';') row = [] itemdct in result:     key in sorted(itemdct.keys()):         row.append("{0}:{1}".format(key, itemdct[key])) csv_writer.writerow(row) 

but output in 1 line.

('a',):3;('b',):4;('c', 'd'):3;('e', 'f'):3;...... 

mydict this

{('a',): 3, ('b', 'c'): 3, ....} 

and result this

[{('a',): 3, ('b', 'c'): 3,.....}] 

thank in advance..

edit: want output this:

('a',):3;('c',):4;('c',):5;('d',):6;('e',):3 ('a', 'c'):3;('b', 'd'):3;('c', 'd'):4 

you can sort items of dictionary according key length. can use groupby group key length , print each group.

def printdict(mydict):     itertools import groupby     def sortfunc(item):         return len(item[0])      sorteditems = sorted(mydict.items(), key=sortfunc)     groups = groupby(sorteditems, sortfunc)     _, group in groups:                  print( ';'.join('%s:%s' % entry entry in group)) 

output:

>>> printdict({('a',): 4, ('b',): 5, ('c', 'd'): 3, ('e', 'f'): 4, ('g', 'h'): 3, ('i',): 3}) ('a',):4;('i',):3;('b',):5 ('e', 'f'):4;('g', 'h'):3;('c', 'd'):3